PtF6 was first prepared by reaction of fluorine with platinum metal.2 This route remains the method of choice.3
PtF6 can also be prepared by disproportionation of the pentafluoride (PtF5), with the tetrafluoride (PtF4) as a byproduct. The required PtF5 can be obtained by fluorinating PtCl2:
Platinum hexafluoride can gain an electron to form the hexafluoroplatinate anion, PtF−6. It is formed by reacting platinum hexafluoride with relatively uncationisable elements and compounds, for example with xenon to form "XePtF6" (actually a mixture of XeFPtF5, XeFPt2F11, and Xe2F3PtF6), known as xenon hexafluoroplatinate. The discovery of this reaction in 1962 proved that noble gases form chemical compounds. Previous to the experiment with xenon, PtF6 had been shown to react with oxygen to form [O2]+[PtF6]−, dioxygenyl hexafluoroplatinate.
Drews, Thomas; Supeł, Joanna; Hagenbach, Adelheid; Seppelt, Konrad (2006). "Solid State Molecular Structures of Transition Metal Hexafluorides". Inorganic Chemistry. 45 (9): 3782–3788. doi:10.1021/ic052029f. PMID 16634614. /wiki/Doi_(identifier) ↩
Weinstock, B.; Claassen, H. H.; Malm, J. G. (1957). "Platinum Hexafluoride". Journal of the American Chemical Society. 79 (21): 5832. doi:10.1021/ja01578a073. /wiki/Doi_(identifier) ↩